Power consumption 650 watt power supply?

La
9

I wanted to ask how much electricity or what it costs me in electricity costs (per hour)

I have:

650 watt power supply

gtx 1060 6gb oc

Ryzen 5 1600

I use the PC for about 3 hours a day (often more, sometimes less) …

I only play Minecraft Multyplayer (if that makes a difference)

I look forward to every answer, thank you in advance.

Ca

With full utilization and an efficiency level of 90%:

Your power supply will almost certainly never run at full capacity. Accordingly, only one measuring device provides an adequate statement.

pe

The easiest way to use sockets electricity meter then you get actual consumption

https://www.test.de/Strommessgeraete-Nur-eins-ist-gut-1781202-0/

Ch

The maximum power of a power supply says nothing about how much electricity is consumed, because it depends on the consumer. You can buy a measuring device for a few EUR.

El

Some energy providers also lend them. But at the prices that these things cost you can also buy one

Sh

You can't calculate the actual consumption and the reason for this is simple:

Just because your power adapter says 650Watt does not mean that it will be automatically burned around the clock when the device is switched on. This is only the specification for Pmax of your power supply. So the performance that you can expect from the thing or deliver maximum according to the manufacturer without there being any problems, Ptot is reached and the device is destroyed and or a protective circuit in the device jumps in around it Protect the device against overload so that the current can't continue to rise.

What can be calculated is what would happen if the device delivered non-stop Pmax (nominal power) for a period of 3 hours.

To do this, first calculate your performance so that you get Killowatt / hour.

650Watt for an hour, 650Watt / hour are only one kilo and you get 0.650 Killowatt / hour short KW / h. You multiply the whole by 3 because we want the whole thing for a total of 3 hours and we have 1.95KW / h

Now all you have to do is know what you pay the pro killowatt / hour and multiply this value by the result. Then you know how expensive it would be if the power supply Nonnstop pulled 650 watts.

ATTENTION! Unfortunately, the world is not as beautiful as we would like it to be, so there are losses and you have to pay, because something is done and electrical energy is converted into another form of energy. Cables are getting warm, transformers have a lot of losses, magnetic fields close in the air instead of what we actually want in the iron core, eddy currents are generated in the iron core by induced voltages that heat the iron core, etc.

The greatest interest of an electrician is always to convert as much electrical energy as possible exactly into the form of energy that we also expect in the system instead of generating undesirable side effects such as heat. However, this does not always clap 100%

The best example of this is the replacement of the light bulb, or what I like to call the light bulb, due to the light-emitting diode. While most of the energy in the incandescent fruit was converted into heat instead of the form of energy that we would have expected, namely light, the light bulb could be called a heater rather than a lamp. All too often I burned my paws when unscrewing light bulbs.

The light bulb has converted more precious energy into heat for which you paid, although you did not necessarily want the heat. What you wanted for your money was light, but it was significantly less. The efficiency of the lightbulb was simply said to throw up in good German.

Then, over time, the LED came onto the market and the special way in which LEDs work made the efficiency significantly better. It was now converted more into light than into heat and you finally got some of your money. You can test it. Touch a lightbulb when it's on and an LED. The LED is still warm due to all the electronics, but it is significantly cooler.

Whether light bulb, PC or electric motor. Each electrical device has an efficiency which is given in% and here, in principle, the only thing that is looked at is what power the device consumes and what physical power the device outputs in relation to the expected form of energy. Briefly P supplied and P released (Pzu and Pab) are compared with each other and the efficiency in% is calculated based on this. The efficiency then says how much% of the supplied power is converted into the power by the system in the expected form of energy. So in the example of the light bulb, how much% of the electrical power supplied is converted into light. The rest do not simply disappear, otherwise we would have a problem with the energy conservation law no, the rest will be converted into another form of energy, which the system simply can't avoid and which the respective system simply brings with it. Cables are e.g. Well, warm when a current flows through them, that is part of it. You can't avoid it unless you are using a superconductor, but as far as I know it has not yet been possible to use such a conductor for ordinary house installations.

the rest of the service is a service that we do not expect from the system or that we do not

La

Thank you for taking the time.

La

OK thanks

La

Thank you for your answer

Sh

I'm happy to help you.