I have another question. In fact:
I'm developing in C # a program with which you can connect to a vServer / root server via SSH, which even works, the only problem is that I want to use the program the Minecraft console.
I can create a screen over the program (daemon), only I can't send commands to this screen.
I've seen that with 'screen -x name -X command' commands can be sent to the screen, but they are not somehow spent in the Minecraft console.
Can someone help me? So in a nutshell, I han made an SSH program in C # with which to use the Minecraft Server console.
You have to open the screen and then the commands
/ usr / bin / screen -S NAME -p 0 -X stuff "COMMAND $ (printf \\\ r)"
This is how it works with the https://github.com/...CHostPanel
But it is PHP, but maybe useful for you
Thank you I will try it
Does it mean I can
/ usr / bin / screen -S NAME -p 0 -X stuff "op test"
Okay, if I enter a command (and by the way at KiTTY in the screen), that is in the command line: say hi $ (printf \ r)
So the "enter" does not work anyway
The partial $ (printf \\\ r) is from PHP to send a Linux line break.
Okay, so the code to send the command looks like this:
consoleWindow.AppendText (client.RunCommand ("/ usr / bin / screen -S server -p 0 -X stuff '" + consoleCommand.Text + "$ (printf \\\ r)'"). Result + Environment.NewLine + Environment.NewLine);
But the $ (printf \\\ r) is written with pure where you usually enter the commands.
Example:
> say test?
[16:37:08 INFO]: [Server] test?
>
> say hi $ (printf \\\ r)
So the 'Enter' is somehow not accepted to say so
You have to first in the screen and then just enter the commands without a /.
Alright, yes, but I want to use a non-terminal program. With the answer of TopicsLP it works, only the commands are not yet "sent".
The 'Enter' is missing, so to speak
Just try it:
/ usr / bin / screen -S server -p 0 -X stuff "COMMAND \\ r"
I believe something like that? Try it, unfortunately have no direct idea of C # serve me from stackoverflow.com
consoleWindow.AppendText (client.RunCommand ("/ usr / bin / screen -S server -p 0 -X stuff '" + consoleCommand.Text + @ "\\ r"). Result + Environment.NewLine + Environment.NewLine);
Thanks alot!
It's worked out! I'm very grateful to you!
Since I developed the program, but progressed through your help, I wanted to ask you if I may add you then in the credits, because of your help here because it is one of the important features, so to speak.
edit:
It was that:
consoleWindow.AppendText (client.RunCommand ("/ usr / bin / screen -S server -p 0 -X stuff '" + consoleCommand.Text + "\\ r'"). Result + Environment.NewLine + Environment.NewLine);
Sure, do you need any information from me? Or is my gamertag enough for you? (is on each platform for each game TopicsLP)
That does not matter I can link you to. For example, Instagram or something similar.
Just have Twitter, https://twitter.com/...m/TopicsLP
Okay I will link your Twitter account and a little thank you letter for your help:-)
No problem, nice evening still I'm off
Thank you likewise
There's still a question, and this:
So how can I do that now the output of the console is displayed in a TextBoy? So how the principle goes, but I know
consoleWindow.AppendText (client.RunCommand ("/ usr / bin / screen -S server -p 0 -X stuff '" + consoleCommand.Text + "\\ r'"). Result + Environment.NewLine + Environment.NewLine);
Does not show it in the TextBox consoleWindows anymore.
Can I somehow do this with 'screen -O'?
Do I have to look at how this can be solved?
I'll see what I find
For example, would it do the following (linux commands):
screen -S test -L screenlog $ (date '+% d.% m.% Y_% H.% M')
Start a screen named "test" and write everything that happens in the screen to the file "screenlog.DATUM_TIME" instead of the date and time you could use a server id or process id for identification.
and then you can with the command:
tail -n 60 screenlog.23.10.2018_17.35
you spend the last 60 lines
tail -n ROW FILE
I hope this helps.
And you do all this every 15 seconds or so.
Thanks, I will try it
